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\section{Main part of Thesis}
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%Začnime rovnicou
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%
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%\begin{equation}\label{r:2}
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%\frac{\ud^2y}{\ud t^2}+\frac{\ud y}{\ud t}+y =0, \qquad y(0)=1, \quad
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%y\,'(0)=15.
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%\end{equation}
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%
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%Grafický priebeh riešenia tejto rovnice vidíme na Obrázku \ref{o:2}.
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%
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%\begin{figure}[ht!]
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%\centering
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%\includegraphics[width=.6\textwidth,angle=0]{relaxcas.pdf}
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%\caption{Teplotná závislosť\/ spinovo-mriežkového relaxačného
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%času}\label{o:3}
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%\end{figure}
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%\tabcolsep=3pt % sirka stlpcov
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%\renewcommand{\arraystretch}{1.2} % riadkovanie
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%\begin{table}[ht!]
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%\centering
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%\caption{Parametre získané z~meraní spinovo-mriežkových relaxačných
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%časov $T_1$}\label{t:2}
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%\medskip
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%\newcolumntype{d}{D{,}{,}{-1}}
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%\begin{tabular}{||c||d|d|d|d|d||}
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%\hhline{|t:==t:==:==:t|}
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%\multicolumn{1}{||c||}{}&\multicolumn{1}{c|}{PP --
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%01}&\multicolumn{1}{c|}{PP -- 05}&\multicolumn{1}{c|}{PP --
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%10}&\multicolumn{1}{c|}{PP -- 16}&\multicolumn{1}{c||}{PP -- 22} \\
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%\hhline{|:==:==:==:|}
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%C $\cdot 10^8$~(s$^{-2}$) & 10,1 & 10,0 & 11,0 & 9,2 & 8 \\
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%\hhline{||-|-|-|-|-|-||}
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%$\tau_0 \cdot 10^{-14}$~(s) & 2,63 & 1,44 & 0,95 & 2,21 & 10,83 \\
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%\hhline{||-|-|-|-|-|-||}
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%$E_{\text a}$~(kJ) & 34,26 & 8,33 & 39,76 & 37,31 & 31,86 \\
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%\hhline{||-|-|-|-|-|-||}
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%$T_{\min}$~(K) & 354 & 367 & 367 & 369 & 367 \\
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%\hhline{||-|-|-|-|-|-||}
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%$T_{1\min}$~(ms) & 141 & 160 & 157 & 175 & 181 \\
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%\hhline{||-|-|-|-|-|-||}
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%$\Delta M_2$~(Gs$^2$) & 5,49 & 5,66 & 5,16 & 5,09 & 5,02 \\
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%\hhline{|b:==b:==:==:b|}
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%\end{tabular}
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%\end{table}
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